X^2-132x+656=0

Solution for X^2-132x+656=0 equation:

X^2-132X+656=0

a = 1; b = -132; c = +656;
Δ = b2-4ac
Δ = -1322-4·1·656
Δ = 14800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14800}=\sqrt{400*37}=\sqrt{400}*\sqrt{37}=20\sqrt{37}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-132)-20\sqrt{37}}{2*1}=\frac{132-20\sqrt{37}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-132)+20\sqrt{37}}{2*1}=\frac{132+20\sqrt{37}}{2}
$